Topic 2 - 2.4 -- Linear Inequalities
Solve for the variable:
a - 3 > 9 Add three to both sides if the inequality.
3 3
a > 12
{a | a > 12} Answer in set builder notation. This says all a such that (|)
a is greater than 12.
(12, ∞) Answer in interval notation. (used in higher Math.) This
says any number from 12, not including 12 to infinity.( ∞ )
Graph The graph on the number line has a open circle on 12 and an arrow
pointing to the right.
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-2m < 24 Divide both sides of the inequality by -2 and remember
-2 -2 when multiplying or dividing both sides of an inequality
m > -12 by a negative number, the inequality changes direction.
{m | m > -12} (turned around).
[-12, ∞) The bracket means the -12 is included in the answer.
It comes from the equal in the problem.
Graph: The graph on the number line has a closed circle on -12 and an
arrow pointing to the right.
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6 - 3y > 9 Add a -6 to both sides of the inequality.
-6 -6
- 3y > 3 Divide by -3. (turn the inequality around)
-3 -3
y < -1
{y | y < -1}
(-∞ , -1]
Graph: The graph on the number line has a closed circle on
-1 and an arrow pointing to the left.
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-6 < y + 5 < 13 This is a compound inequality. Add -5 to the three parts.
-5 -5 -5
-11 < y < 8
{y | -11 < y < 8}
[-11, 8]
Graph: The graph has closed circles on -11 and 8 and shading
between them.
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-15 < 8 - 4k < -8 Add -8 to the three parts of the inequality.
-8 -8 -8
-23 < -4k < -16 Divide all three parts by -4 and turn both inequalities
-4 -4 -4 around.
23/4 > k > 4 Turn the whole inequality around. It is easier to read
4 < k < 23/4 and graph.
{k | 4 < k < 23/4}
[4, 23/4]
Graph: The graph on the number line has solid circles on 4 and 23/4 and the
between them is shaded