Topic 4.3 (Graphing Inequalities)
To graph an inequality, graph the equality (straight line) first and then pick
a coordinate point (usually (0, 0)). If this point shows a true statement
you shade the area (half plane) including the point. If this point shows a
false statement you shade the area that doesn’t contain the point.
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Sample problem
Graph the inequality y £ x + 2 on the grid below.
First graph the equality y = x + 2
m = 1/1, b = 2

After the straight line is shown, substitute the point(0, 0) into the original
inequality. y £ x + 2, (0, 0), 0 £ 0 + 2, 0 £ 2, true - shade down
and to the right (including the point). Remember the straight line is a
solid line because of less than or equal to(£ )in the problem.
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Graph the inequality 3x - 2y > 12.
Solve the equation for y and graph.
3x - 2y = 12 This gives the straight line.
-2y = -3x + 12
y = (3/2) x -6 m = 3/2 b = -6

Draw the straight line. In this case it will be a broken (open) line because
of the greater than(>). This symbol does not contain the equal, so the
straight line is not solid.
Substitute the point (0, 0) into the original inequality.
3x - 2y > 12, (0, 0), 3(0) - 2(0) > 12, 0 - 0 > 12, 0 > 12, False
Shade down and to the right or the region than doesn’t include the
point.
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Graph the following inequality.
x + y ³ 5, y = -x + 5 Solve for y (y = mx + b).
m = -1/1, b = 5 Find the slope and the y-intercept.

The straight line will be solid, because of the greater than or equal to(³ )
Substitute (0, 0) into the inequality 0 + 0 ³ 5, 0 ³ 5, False Shade up
and to the right (the region not including the point). Please notice: the region
shaded is: x + y > 5, the solid line is: x + y = 5, and the region to the left and
down is: x + y < 5